Open a ticket
Chat with us

Lm3915 Calculator -

[ R2 = R1 \times \left( \fracV_\textref1.25 - 1 \right) ]

Then choose ( R_\textin1, R_\textin2 ) as a voltage divider. [ R_\textset = \frac12.5I_\textLED ]

| Problem | Consequence | |---------|--------------| | Choosing R1/R2 for a specific full scale | Incorrect clipping level | | Converting dBu or dBV to required input voltage | Mismatch with line-level audio | | Setting RLO/RHI for offset display (e.g., -20 dB to +10 dB) | First LED never lights | | Resistor selection for precise 1 mA/LED | Burnout or dim display |

[ V_\textRLO = V_\textLO - \text(offset) \quad \textand \quad V_\textRHI = V_\textRLO + \fracV_\textHI - V_\textLO10^(9/10) ]

Desired input at pin 5 for LED10 = 5.0 V (peak). Actual peak input = 1.414 V. Thus, we need gain , not attenuation. Instead, set RHI lower: Use a voltage divider from Vref to set RHI = 1.5 V (peak). Then:

( R_\textset = 12.5 / 0.015 = 833.3 \ \Omega ) → use 820 Ω.

But for simplicity, designers often set ( V_\textRLO = V_\textLO ) and ( V_\textRHI = V_\textref ) (if ( V_\textref ) is scaled to match highest LED threshold). More practically: The LM3915’s internal divider has a ratio of ~1.25 dB per step in voltage terms, so the voltage at step n is:

For a desired max LED at ( V_\textin,peak = V_\textmax ):

RLO = 0 V (ground). RHI = 5.0 V (to reference). But now the highest LED triggers at ( V_\textin \approx 5.0 ) V peak? That’s far above 1.414 V. So we must attenuate input.

[ V_\textin,peak = \sqrt2 \times V_\textrms ]

[ \textAttenuation factor = \fracV_\textref,desiredV_\textmax ]

| Parameter | Formula | Standard value example | |-----------|---------|------------------------| | ( R_\textset ) | 12.5 / I_LED | 620 Ω for 20 mA | | ( V_\textref ) | 1.25 × (1+R2/R1) | 5.0 V: R1=1.2k, R2=3.6k | | LED step voltage (n from 1 to 10) | ( V_\textRLO \times 10^(n-1)/10 ) (if RHI/RLO = 1:0 ratio) | Step 6: ×3.16 from step 1 | | Power (bar mode) | ( 10 \times V_\textLED \times I_\textLED ) | 10×2V×0.02A = 0.4W |

A dedicated calculator solves these with direct equations. 4.1 Reference Voltage Divider (R1, R2) Given desired ( V_\textref ):

Questions? Contact us now
We provide support only in English.
TECHNICAL SUPPORT PHONE
SALES PHONE
Telephone support available from 10 AM till 10 PM Central European Time
Copyright © 2025 Terminalworks. All Rights Reserved