Los Materiales Askeland 3 Edicion — Solucionario Ciencia E Ingenieria De

[ \sqrt{t} = \frac{0,0008}{5.313\times10^{-6}} \approx 150,6 ]

[ 0,71 = \frac{0,0008}{2\sqrt{(1.4\times10^{-11}) t}} ] [ \sqrt{t} = \frac{0,0008}{5

[ \frac{1,2 - 0,45}{1,2 - 0,10} = \frac{0,75}{1,10} = 0,6818 ] [ \sqrt{t} = \frac{0